C++ vs Rust Reference & Dereference 코딩 비교❤️

rust cpp reference dereference training #rust #reference #dereference
https://youtu.be/zaOXxYSm6hk

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c++

#include <iostream>

using namespace std;

int main ()
{
  int number1 = 10;
  int *pointer1 = &number1;

  double number = 23.4;
  double *pointer2 = &number2;

  cout << "Number1 : " << number1 << "(size : " << sizeof(number1) << " ) " << endl;
  cout << "Pointer1 : " << pointer1 << "(size : " << sizeof(pointer1) << " ) " << endl;

  cout << "Number2 : " << number2 << "(size : " << sizeof(number2) << " ) " << endl;
  cout << "Pointer2 : " << pointer2 << "(size : " << sizeof(pointer2) << " ) " << endl;

  return 0;
}

Rust

fn main() {
    let mut number1:i32 = 10;
    let number1_ref = &mut number1;
    let number1_ref_ptr_add = number1_ref.clone();
    *number1_ref = 9; 

    println!("Rust \n Refenrence & Deference & pointer Address");
    println!("Number1 : {} \n size of(number1) :{} \n", number1, std::mem::size_of_val(&number1));
    println!("Number1 pointer address : {:p}", &number1_ref_ptr_add); 


    let mut float64_02:f64 = 23.456;
    let float64_02_ref = &mut float64_02;
    let float64_02_ref_ptr_add = float64_02_ref.clone();
    *float64_02_ref = 45.678; 

    println!("Rust \n Refenrence & Deference & pointer Address");
    println!("float64_02 : {} \n size of(float64_02) :{} \n", float64_02, std::mem::size_of_val(&float64_02));
    println!("Float64_02 pointer address : {:p}", float64_02_ref_ptr_add);

}

f64
println!("Float64_02 pointer address : {:p}", float64_02_ref_ptr_add);
| ^^^^^^^^^^^^^^^^^^^^^^ the trait `Pointer` is not implemented for `f64`
|
note: required by a bound in `ArgumentV1::<'a>::new_pointer`
= note: this error originates in the macro `$crate::format_args_nl` (in Nightly builds, run with -Z macro-backtrace for more info)


이 오류 해결 해야함

해결책
https://doc.rust-lang.org/std/primitive.f64.html

f64 - Rust

최종

fn main() {
    let mut number1:i32 = 10;
    let number1_ref = &mut number1;
    let number1_ref_ptr_add = number1_ref.clone();
    *number1_ref = 9; 

    println!("Rust \n i32 \n Refenrence & Deference & pointer Address");
    println!("Number1 : {} \n size of(number1) : {}", number1, std::mem::size_of_val(&number1));
    println!("Number1 pointer address : {:p}", &number1_ref_ptr_add); 


    let mut float64_02:f64 = 23.456;
    let float64_02_ref = &mut float64_02;
    let float64_02_ref_ptr_add = float64_02_ref.clone();
    *float64_02_ref = 45.678;
    let f64_add = float64_02_ref_ptr_add.to_bits();
    

    println!("\n f64 \n Refenrence & Deference & pointer Address");
    println!("float64_02 : {} \n size of(float64_02) : {}", float64_02, std::mem::size_of_val(&float64_02));
    println!("Float64_02 pointer address : {:p}", &f64_add);

}
}

easy rust 018 -
mutable references
https://youtu.be/1ZOf5MD-L3E

easy_rust 043:
Dereferencing , . operator
https://youtu.be/znCUAqyfbe4

rust : 117- Deref trait
https://youtu.be/tFC8ZWvMDOE

rust 변수 메모리 주소 출력하는 방법
https://stackoverflow.com/questions/46683073/why-is-the-memory-address-printed-with-p-much-bigger-than-my-ram-specs

Why is the memory address printed with {:p} much bigger than my RAM specs?

rust Deref
https://stackoverflow.com/questions/27938260/what-happens-when-i-write-to-a-random-memory-address

What happens when I write to a random memory address?

 

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Go에서 pointer개념
https://developpaper.com/go-advanced-feature-12-pointer-explanation-under-what-circumstances-should-pointers-be-used/

Go advanced feature 12 | pointer explanation: under what circumstances should pointers be used? - Develop Paper

 

 

 

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출처 : 노마드 코더 Nomad Coders

https://nomadcoders.co/javascript-for-beginners

바닐라 JS로 크롬 앱 만들기 – 노마드 코더 Nomad Coders

[JavaScript]NaN은 Not a Number(숫자가 아님)이라는 뜻

https://economiceco.tistory.com/10947

[JavaScript]NaN은 Not a Number(숫자가 아님)이라는 뜻

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